x=-b+/- multipled by the square root of b squared - 4 ac

Question

anonymous · Answer

yes?

myininaya · Answer

$$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$$

anonymous · Answer

ok look my teacher gave us some equations and one of them are $${x}^2+6x+9=0$$
and the answeres are x=-3 so i dont get it

anonymous · Answer

yes, this is (x+3)^2 so x = -3

anonymous · Answer

ok ;) so how do iget the answer for the first one

anonymous · Answer

Take the coefficient of the terms:
i.e. the function is in ax^2+bx+c=0 form and plug the values of a, b, and c into the formula myiniaya posted, that is one way.

anonymous · Answer

which one is the first one?

anonymous · Answer

the first one is $$x=-b \pm \sqrt{b ^{2}- 4ac} \div 2a$$ ;D

myininaya · Answer

what do you want to solve for?

anonymous · Answer

what about it?

myininaya · Answer

we can solve it for b, a, or c?
its already solved for x

anonymous · Answer

that is the quadratic formula to find roots.

anonymous · Answer

well yeah the teacher wants us to find  all thee a b and c but i dont reallly know how!

myininaya · Answer

she wants you to solve the quadratic formula for a
then b
then c
are you sure?

anonymous · Answer

yes thats what she said :S

myininaya · Answer

k let's see if we can do it 
let's try to solve for a first

anonymous · Answer

ok ;D

anonymous · Answer

it is impossible to solve this equation for a b and c

myininaya · Answer

one sec

myininaya · Answer

i think you can use the quadratic formula to solve for a lol

anonymous · Answer

which is??

myininaya · Answer

attachment

anonymous · Answer

yes, but it impossible to solve for all three values of a,b and c

myininaya · Answer

lol. i honestly don't think this what your teacher wants

myininaya · Answer

i can solve for b and c
use the quad on b
and c is easiest

anonymous · Answer

no, you cannot. x can hold only two values. you need atleast 3 equations to solve for 3 unknown variables.

myininaya · Answer

a doeesnt have to be both 
it can be one or the other
just like x

anonymous · Answer

you may be able to get a,b and c in terms of the other variables, but that doesn't get you any closer to solving for them.

myininaya · Answer

right but it sounded like he wanted us to solve the quadratic formula for each lol

anonymous · Answer

oh, that is just an exercise in stupidity.

anonymous · Answer

there is no point of that. I don't think their teacher asked them to solve for a,b and c.

myininaya · Answer

me neither