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Mathematics 9 Online
OpenStudy (toxicsugar22):

hi who can help me

OpenStudy (anonymous):

with?

OpenStudy (toxicsugar22):

Find the first terms of the product in ascending powers. (1-2x^2-x^4)(4+x^2-2x^4)

OpenStudy (toxicsugar22):

i know u helped me before but i am stuck

OpenStudy (toxicsugar22):

please somone help me

OpenStudy (anonymous):

oh ive already done this for you in detail. i dont understand why you keep reposting this.

OpenStudy (toxicsugar22):

no this is a diffeent one and i am stuck

OpenStudy (anonymous):

(a+b)(c+d) = ac+ad+bc+bd. similarly expand your problem and post what you get

OpenStudy (toxicsugar22):

1-4+x^2+x^4

OpenStudy (toxicsugar22):

is it right

OpenStudy (toxicsugar22):

can u help me

OpenStudy (toxicsugar22):

please

OpenStudy (anonymous):

hold on. stop spamming. let me read what you posted,

OpenStudy (anonymous):

LOL I THOUGHT THE SAMMEEE THING

OpenStudy (toxicsugar22):

what

OpenStudy (anonymous):

no that is wrong, toxic

OpenStudy (toxicsugar22):

ok can u help me further Ill repay you

OpenStudy (anonymous):

repay me with what?

OpenStudy (toxicsugar22):

nm

OpenStudy (toxicsugar22):

can u help me please?

OpenStudy (toxicsugar22):

or can u tell me a wesite that provides free online tutoring

OpenStudy (anonymous):

yes. use khan academy

OpenStudy (anonymous):

do you understand algebra?

OpenStudy (toxicsugar22):

yes

OpenStudy (toxicsugar22):

but not really

OpenStudy (anonymous):

okay. then you understand that (a+b)(c-d) = ac -ad +bc - bd ?

OpenStudy (toxicsugar22):

yes

OpenStudy (toxicsugar22):

well

OpenStudy (toxicsugar22):

well hello

OpenStudy (anonymous):

then do you understand that \[(1-2x ^{2}-x ^{4})(4+x ^{2}-2x ^{4})\] is equal to \[(1 \times 4 +1 \times x ^{2}-1 \times 2x ^{2}) -(2x ^{2} \times4+2x ^{2}\times x ^{2}-2x ^{2}\times 2x ^{4})\] \[-(x ^{4}\times 4 +x ^{4} \times x ^{2}-x ^{4}\times 2x ^{4})\] ?

OpenStudy (toxicsugar22):

yes

OpenStudy (toxicsugar22):

ok

OpenStudy (anonymous):

can you add all the x terms and x^2 terms and so on and post it here?

OpenStudy (anonymous):

i am sorry, the first term in the equation i posted has -1 times 2x^2 in the end, it is supposed to be -1 times 2x^4

OpenStudy (toxicsugar22):

-5+x^2-7x^2

OpenStudy (toxicsugar22):

i guess is it right

OpenStudy (anonymous):

no its not

OpenStudy (anonymous):

where did you get -5 from?

OpenStudy (toxicsugar22):

oops sorry 4

OpenStudy (toxicsugar22):

help me

OpenStudy (toxicsugar22):

please

OpenStudy (anonymous):

yes 4 is the first one.

OpenStudy (anonymous):

-7x^2 is also correct

OpenStudy (anonymous):

your answer is wrong. -5+x^2-7x^2 cannot be the answer. where did you get x^2-7x^2 from? isn't that just -6x^2?

OpenStudy (toxicsugar22):

so what is the answer

OpenStudy (toxicsugar22):

is it 4-7x^2-6x^2

OpenStudy (toxicsugar22):

is it right can u hel p

OpenStudy (anonymous):

why do you have a -6x^2 there? -7x^2 - 6x^2 = -13x^2

OpenStudy (anonymous):

that is not the answer.

OpenStudy (anonymous):

can you just use the expansion I gave you and write out fully what you would get?

OpenStudy (anonymous):

instead of guessing the answer like this?

OpenStudy (toxicsugar22):

ok i got 4-7x^2-6x^23

OpenStudy (toxicsugar22):

is it right if not can u help me

OpenStudy (anonymous):

what do you mean by 6 x^23?

OpenStudy (toxicsugar22):

sorry 6x^2

OpenStudy (anonymous):

I am not gonna help you until you write down and expand the expression I gave you.

OpenStudy (anonymous):

that is the only way you will get the answer. you are just guessing the answer here.

OpenStudy (toxicsugar22):

didnt i do that

OpenStudy (anonymous):

no you did not.

OpenStudy (toxicsugar22):

i dont know what u mean

OpenStudy (toxicsugar22):

can u explain

OpenStudy (anonymous):

is it that hard to multiply 4 times 1?

OpenStudy (toxicsugar22):

4

OpenStudy (anonymous):

right. so scroll up. and do all the multiplications I showed you in my expression and post your answer. then we will figure out the answer together.

OpenStudy (anonymous):

(1×4+1×x^2−1×2x^4) = (4 +x^2 -2x^4) similarly write down the other two separately and post them here

OpenStudy (toxicsugar22):

i am sorry for being diffuct but i dont get what u said

OpenStudy (anonymous):

then you shouldn't take math. Sorry I cannot help you any more.

OpenStudy (anonymous):

take my advice and drop math. its not your strong suit

OpenStudy (toxicsugar22):

ok i got it

OpenStudy (toxicsugar22):

canu just write down the second equation for me i see it but can u do that for me so i can copy and paste

OpenStudy (anonymous):

no.

OpenStudy (toxicsugar22):

ok i got -4x^2+2x^4+8x^2

OpenStudy (toxicsugar22):

is it right

OpenStudy (toxicsugar22):

and can u not be rue

OpenStudy (toxicsugar22):

rude

OpenStudy (toxicsugar22):

is it right

OpenStudy (anonymous):

no it is not. do you know what a^2 times a^2 =?

OpenStudy (toxicsugar22):

a^4

OpenStudy (anonymous):

(2x^2×4+2x^2×x^2−2x^2×2x^4) = ?

OpenStudy (anonymous):

(2x^2×4+2x^2×x^2−2x^2×2x^4) = ( (2x^2×4) + (2x^2×x^2) − (2x^2×2x^4) )

OpenStudy (anonymous):

now multiply the individual products within each brackets and write down the answer

OpenStudy (toxicsugar22):

8x^2+2x^4-4x^6

OpenStudy (toxicsugar22):

is it right

OpenStudy (anonymous):

yes thats right. now do the last one too and post your answer

OpenStudy (toxicsugar22):

-4x^6

OpenStudy (toxicsugar22):

right

OpenStudy (anonymous):

no i meant the third expression in the big expression I gave you

OpenStudy (anonymous):

(x^4×4+x^4×x^2−x^4×2x^4) = ?

OpenStudy (toxicsugar22):

ok i got -2x^8+x^6+4x^4

OpenStudy (toxicsugar22):

is it right

OpenStudy (anonymous):

yes. that is right.

OpenStudy (anonymous):

so now do (4 +x^2 -2x^4) - (8x^2+2x^4-4x^6) - (-2x^8+x^6+4x^4) and post your answer

OpenStudy (toxicsugar22):

ok i got -8x^4-7x^2+4+3x^6-2x^8

OpenStudy (toxicsugar22):

is it right

OpenStudy (anonymous):

yes thats right. now just write this expression in ascending powers.

OpenStudy (toxicsugar22):

ok 4-7x^2-8x^4

OpenStudy (toxicsugar22):

is it right

OpenStudy (anonymous):

those are the first three terms in ascending powers of x

OpenStudy (anonymous):

so yes, that is your answer. bye

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