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Mathematics 20 Online
OpenStudy (anonymous):

integral of 625x^3(e^5x), use integration by parts

OpenStudy (anonymous):

i know how to start it off, i just keep getting the wrong anser tho

OpenStudy (anonymous):

long integration involves, select 625x^3 as a first function

OpenStudy (anonymous):

what did u get?

OpenStudy (anonymous):

i got \[e^5x(125x^3-75x^2-30x-6)+C\]

OpenStudy (anonymous):

e^(5x)*

OpenStudy (anonymous):

when u select 625x^3 as a first function, u write the derivative of it,right?

OpenStudy (anonymous):

power must be reduced

OpenStudy (anonymous):

i followed an example in the book, and it used x^3 as the u value, and 625e^5x as va

OpenStudy (anonymous):

v

OpenStudy (anonymous):

u mean the reduction formula

OpenStudy (anonymous):

use 5x = t t^3 (e^t)dt

OpenStudy (anonymous):

then use integral by parts

OpenStudy (anonymous):

what reduction formula did u use?

OpenStudy (anonymous):

him is right

OpenStudy (anonymous):

m e?

OpenStudy (anonymous):

ok i got the write answer now,lol sorry nvrmind, but thanks guys :)

OpenStudy (anonymous):

things got easy now

OpenStudy (anonymous):

no him it wasnt you :)

OpenStudy (anonymous):

ok amk....

OpenStudy (anonymous):

glad 2 help...

OpenStudy (anonymous):

so him...u feeling fresh now? :)

OpenStudy (anonymous):

thnx fr asking...yeah better now..nthn a coke wont heal

OpenStudy (anonymous):

medal for ur determination :)

OpenStudy (anonymous):

u must feel much better now:P

OpenStudy (anonymous):

yeah thnx

OpenStudy (anonymous):

:)

myininaya (myininaya):

well i just did all of this work without reading any of that above stuff so here you go lol

OpenStudy (anonymous):

myin: the anser was actually (125x^3-75x^2+30x-6)e^5x +C, u were right with the first two numbers, but thanku so much for taking the time to work it out :)

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