integral of 625x^3(e^5x), use integration by parts
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OpenStudy (anonymous):
i know how to start it off, i just keep getting the wrong anser tho
OpenStudy (anonymous):
long integration involves, select 625x^3 as a first function
OpenStudy (anonymous):
what did u get?
OpenStudy (anonymous):
i got \[e^5x(125x^3-75x^2-30x-6)+C\]
OpenStudy (anonymous):
e^(5x)*
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OpenStudy (anonymous):
when u select 625x^3 as a first function, u write the derivative of it,right?
OpenStudy (anonymous):
power must be reduced
OpenStudy (anonymous):
i followed an example in the book, and it used x^3 as the u value, and 625e^5x as va
OpenStudy (anonymous):
v
OpenStudy (anonymous):
u mean the reduction formula
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OpenStudy (anonymous):
use 5x = t
t^3 (e^t)dt
OpenStudy (anonymous):
then use integral by parts
OpenStudy (anonymous):
what reduction formula did u use?
OpenStudy (anonymous):
him is right
OpenStudy (anonymous):
m e?
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OpenStudy (anonymous):
ok i got the write answer now,lol sorry nvrmind, but thanks guys :)
OpenStudy (anonymous):
things got easy now
OpenStudy (anonymous):
no him it wasnt you :)
OpenStudy (anonymous):
ok amk....
OpenStudy (anonymous):
glad 2 help...
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OpenStudy (anonymous):
so him...u feeling fresh now? :)
OpenStudy (anonymous):
thnx fr asking...yeah better now..nthn a coke wont heal
OpenStudy (anonymous):
medal for ur determination :)
OpenStudy (anonymous):
u must feel much better now:P
OpenStudy (anonymous):
yeah thnx
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OpenStudy (anonymous):
:)
myininaya (myininaya):
well i just did all of this work without reading any of that above stuff so here you go lol
OpenStudy (anonymous):
myin: the anser was actually (125x^3-75x^2+30x-6)e^5x +C, u were right with the first two numbers, but thanku so much for taking the time to work it out :)