Question

use the square root property to solve the quadratic equation
(x-3)^2=4
a.x=7 b.x=1,-5 c. x=5,1 d. x=2,-2

Answer 1

First of all:

(x-3)^2=4
\[\sqrt{(x-3)^{2}}= \pm \sqrt{4}\]
\[x-3 = \pm 2 \]
\[\left\{ 1,5 \right\}\]

Answer 2

Taking the square root of \[(x - 3)^{2}\] saves you a lot of work since 4 is a perfect square. This method is great for solving exercises like this one.

Answer 3

thanks :)