each digit 0,1,2,3,4,5,6,7,8, an 9 is writting on a slip of paper and the slips are placed in a hat. if 3 slips of paper are selected at ramdom find the probl that the 3 numbers are greater then 5
3/10
i mean 4/10
No
It's \[\frac{4 \choose 3}{10 \choose 3}\]
there are ten choose 3 ways to choose three numbers out of ten ten choose 3 is 10*9*8/3/2=120 . This is your denominator. There are 4 choose 3 ways to choose the 4 of the ten numbers that are greater than 5. 4 choose 3 is 4. answer is 4/120 = 1/30
Yeah, that's what I said ;p
yup. couldn't find n choose k in the template.
I always write equations manually. It's all just latex =) { n \choose k}
much easier than using the editor
thanks for the tip. {x\times y}\[\frac{a}{b}\] just testing
oops didnt work
You have to be sure your equation is inside the \[ \ ] bits (no space)
\[x \times y\]
\[\frac{a}{b}\]
damn
\[x\cdot y, \forall x \in N, f(g(x)) = (f\circ g)(x)\]
Hrm? you are making fractions?
trying to typed \[\frac{a}{b}\]
it's working for me.. (I can see a over b)
it looks good in preview but doesn't post right
i see no fraction bar!
\[x\times y\]
got one
\[{n \choose k}\]
got it
Sometimes the fraction bar doesn't show up for you when you post stuff. if you go to a different question and come back it can fix itself.
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