Question

How do I find the domain of f(x) = (-x^2+16/x^2-2x-3)

Answer 1

whenever you have a fraction function, the domain will be:

(bottom part) > 0

Answer 2

false; it is all x values that will make the bottom not equal to 0.

Answer 3

so, \[x^{2} - 2x - 3 \neq 0 \]
solve for x and it'll give yu yur domain

Answer 4

set the denominator = 0 solve.
x^2-2x-3=0
(x+1)(x-3)=0
x=-1 or x = 3
domain is all real numbers except -1 and 3