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Assume x can represent any real number. Use absolute value notation when necessary. sqrt(36^(2))
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There is no x there.
My bad. I meant sqrt(36x^(2))
\[\sqrt{36x^{2}} = 6x\]
so the solution is 6x?
assuming of course that x is positive. it is actually 6 times absolute value of x, in case x is negative.
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so it can be both 6x and -6x
It's 6|x|
oh okay, thaks
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