Question

11 pictchers, 7 infielders, and 12 other players. if 3 players are selected at ramdom, determine the probl that all 3 are infliders

Answer 1

OK so we start off the same way!

Answer 2

Yes, you can do this, it is just like the other two...

Answer 3

7/30?

Answer 4

for the first selection, yes, now what for the second? (remember that one infielder is removed by you choosing him.

Answer 5

6/29

Answer 6

right, then the third selection...

Answer 7

5/28

Answer 8

okay, now multiply...

Answer 9

so u do 30 times 29 times 28?

Answer 10

cancel first... it's easier

Answer 11

then 6 times 5 times 4?

Answer 12

I mean 7,6 and 5?

Answer 13

(7*6*5)/(30*29*28) ...the 6*5 cancels with the 30, making it easier

Answer 14

...=7/(29*28)

Answer 15

oh, wait keep canceling...

Answer 16

7/28 = 1/4 so 7/(28*29) = 1/(4*29)

Answer 17

what?

Answer 18

7 times 6 times 5 is 210

Answer 19

yes, but it is easier to cancel before you multiply than to multiply then reduce

Answer 20

so what would it be when u cancel 210/2?

Answer 21

do you want to wrangle with reducing 210/24360?

Answer 22

210/24360 = 1/116

Answer 23

116?

Answer 24

Great job on figuring out the probability part, we only got hung up on the arithmetic. When is the quiz?

Answer 25

Well I am doing h/w now and then next week he usually gives us the quiz like after monday

Answer 26

then we have a week to work on it