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Express the integral as function of x.
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\[\int\limits_{1}^{x^2}((d/dt)\sqrt{t^7 +3})\]
Integrate\[(t ^{7}+3)^{1/2}\]
let f(t) = sqrt(t^7 +3) therefore we want the integral \[\int\limits_{1}^{x^2} f' (t) dt\]
now by the fundamental theorm of cal this equals \[f(x^2) -f(1) \]
= sqrt(x^14 +3) - sqrt(4)
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