solve for x: log(1-x) - log(8+x) = 1
I got this so far: (1-x/8+x) = 10
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OpenStudy (anonymous):
multiply both sides by (8+x) and post what you get.
OpenStudy (anonymous):
ok. (8/16+x^2) = 80+10x
OpenStudy (anonymous):
thats wrong i know it
OpenStudy (anonymous):
yup, it is catastrophically wrong.
OpenStudy (anonymous):
ok im retarded maybe its the caffeine buz
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OpenStudy (anonymous):
please explain why u have to multiply by 8+x on both. why not 1-x on both?
OpenStudy (anonymous):
always be clear in what you are writing. use brackets to make your meaning clear.
it is (1-x)/(8+x) = 10
multiply by (8+x) on both sides
(1-x)*(8+x)/(8+x) = 80+10x
the (8+x) cancels out in the numerator and denomiator on the left hand side, leaving
1-x = 80+10x.
I trust you can take it from there?
OpenStudy (anonymous):
Yes thanx
OpenStudy (anonymous):
x=79/11
OpenStudy (anonymous):
you multiply by 8+x since you want to cancel it out from the denominator.
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