Question

y=x2+4 can someone help me wth this graph equation i need to find the vertex and the intercepts

Answer 1

do you mean y = x^2 + 4?

Answer 2

yes

Answer 3

so the standard parabola is y = mx+b where b is the y-intercept
so in your equation y = x^2 + 4 so the y-intercept = 4, or (0,4)

Answer 4

and the x-intercepts are (2,0) and (-2,0) by putting y=0

Answer 5

y=0^2 +4
y=4
y_intercept is 4

0 = x^2 +4
-4 = x^2
No real x_intercepts

vertex:
a=1, b=0, c=4
x=-b/2a
x=0/2 = 0
y = 0^2+4 = 4
vertex: (0,4)

Answer 6

oh pellet..looks lyk an off day

Answer 7

dumbcows right

Answer 8

thanks everyone

Answer 9

i ate a dumbcow at mcdonalds once.... with cheese and a bun and extra pickles...
it was mighty tasty :)