Question

8z^2-64
when factored out does this equal
8(z-8)(z+8)

Answer 1

8 ( z^2 - 8 )

Answer 2

when you factor out the 8 you need to divide the 64 by 8 as well

Answer 3

its just a matter of taking the time to multiply it all together again; you can do it :)

Answer 4

so when i multiply it all back out it gives me my 8z^2-64
ohhhh ok lol im just trying to get other peoples opinions o my answers and check my answers for an assighnment i have

Answer 5

(2z sqrt(2) +8) (2z sqrt(2) -8) is what i get

Answer 6

8.8.8 > 64

Answer 7

we arent supposed to use the quadratic equation we dont learn that til junior year

Answer 8

this factors to a difference of squares

Answer 9

your original conclusion there is wrong

Answer 10

but when i multiply it all back it gives me the original equation

Answer 11

?

Answer 12

what would it equal then cause its confusing me

Answer 13

\[= 8 ( z^2 -8 )\]\[= 8 ( z-\sqrt{8})(z+\sqrt{8})\]

Answer 14

thats it , noting else

Answer 15

or you could write it as \[8 ( z-2\sqrt{2})(z+2\sqrt{2})\]

as \[\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2\sqrt{2}\]