Question

Consider the following.

Answer 1

8

Answer 2

g(x)=x\[\sqrt{2-x}\]
Use a graphing utility to approximate the relative minimum or relative maximum value of the function

Answer 3

V2-x goes next to =x

Answer 4

square roots dont have a relative min or max..... unless its their endpoints

Answer 5

it does
but the end point is not giving

Answer 6

youre going to have to rewrite the question to make sense of it for us :)

Answer 7

so is infinitY/

Answer 8

ok

Answer 9

\[g(x)=\sqrt{2-x}\]

Answer 10

and x is next to V2-x

Answer 11

so is g(x)=xV(2-x)

Answer 12

domain is x<=2
relative maximum at x=4/3
i used calculus and set derivative equal to 0

Answer 13

relative maximum at x=4/3, why not a cordinate?

Answer 14

to get y coordinate substitute 4/3 for x
y = 4/3 * sqrt(2-4/3)

Answer 15

so you get, g(4/3)=4/3V(2-3/4)

Answer 16

you need to find a graphing calculator or grAPHING COMPUTER software to see it visually
which i think is what the question is asking

Answer 17

yeah, the is what it asking

but like somebody above said, square root fuction don't have a maximun or minimum. Then how you find it?

Answer 18

no they dont but g(x) does because it has the x out front of the sqrt

Answer 19

i don't got a graphing calculator

Answer 20

and i search in the internet,but din't find any that could graph square root functions

Answer 21

try this
http://www.graphcalc.com/download.shtml

Answer 22

i got a similar problem, with the answe,r wanna me to show you?

Answer 23

i am using schoool computer , cannot dowload the.

Answer 24

ok, is this a calculus class?

Answer 25

pre

Answer 26

ok for last problem you def need the graph or plot the points from 0 to 2 to see the maximum

Answer 27

did you dowload the graph program?

Answer 28

yeah i used it to graph your function:)

Answer 29

what did you get?

Answer 30

the domain, is x<_2 , right?

Answer 31

yes
here is the graph

Answer 32

oh, it looks different from what i thought it would be .

Answer 33

thats because of the x in front

Answer 34

nice., so what does the x do? slope>?

Answer 35

?

Answer 36

what are the point of the maximun

Answer 37

kinda, it changes the direction of the graph
when sqrt(2-x) might be decreasing as x increases
when you multiply by x, it increases to a point

the max is the highest point on graph, x=4/3

Answer 38

cordinate?

Answer 39

i told you earlier, plug in 4/3 into function
look at cursor position on right side of picture
i left it at approx where the max is

Answer 40

so it be (1.37,?

Answer 41

use trace on the graph, to find the highest point.

Answer 42

use trace on the graph, to find the highest point.

Answer 43

yes something like that

Answer 44

i need the exact point.

Answer 45

from a graph you will only get an approximate but thats all you need right now
the exact answer i already told you
max: (4/3, 4/3*sqrt(2-(4/3)))

Answer 46

don't got a caclculator iwth me, bye, i will solve it when ig et home.

Answer 47

wow
y = 1.088