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write the slope intercept equation for the line that passes thru (-2,3) and perpendicular to 2x-9y=-12. show work
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ok, so the slope intercept equation is y=mx + b
but first you should isolate y in the equation you already have. So you can isolate the rate of change aka the mx part.
-9y = -2x - 12 then: y = (2/9)x - 12/9 to simplify: y =(2/9)x - 4/3 aka 1 1/3
so then, as its perpendicular, you'll know that the slope of the opposite line is the negative recipricol. in this case, -9/2x
then, input (-2,3) respectfully in the x and y places in the now modified equation. so you get: 3 = (-9/2)(-2) + b so: 3 = 9 + b then: -6 = b
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so you end up with y=-9/2x - 6
Hope that helped. medal, s'il vous plait? :)
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