Question

how do u write the standard equation and graph the parabola 12(x+6)=(y-4)^2 ?

Answer 1

Because y is going to be squared and you want the standard equation
ax^2 + bx + c
expand (y-4)^2
you should get

12(x+6) = y^2 -8y + 16
now divide both sides by 12

x+6 = (1/12)y^1/2 - (2/3)y + (4/3)

now subtract 6 from both sides and your standard equation in terms of y is:
x=(1/12)y^1/2 - (2/3)y + (22/3)


I sent a really crappy graph of what it will somewhat look like...dont think that is the way it is though, its just an approximation to let you know if yours is right