Question

A circle is defined by the following equation:
3x^(2)+3y^(2)-24x+42y+183=0
What is its radius?

Answer 1

i get \[\sqrt{126}\]

Answer 2

let me try it slowly.
\[3x^3+3y^3-24x+42y=-183\]
\[x^2-8x + y^2 +14y=-61\]
\[(x-4)^2+(y-7)^2=-61+16+49=4\]
radius is 2

Answer 3

should be \[(x-4)^2+(y+7)^2=4\]
doesn't matter for radius, but center is (4,-7) not (4,7)
hope the steps are clear: make the coefficient of the square terms 1 and then complete the square.

Answer 4

where did you get the cubes from?