Given f(x)=2x+3 and g(x)=1/2(x-3), find the each composition. I am confuse how to set then up.
a composition is f(g(x)) nd g(f(x)), where you substitute the whole other function for x
yeah,
you start from the inside to the outside, but i still confuse how to set them up.
f(g(x)) = 2(g(x)) + 3
f(x)=2x+3 and g(x)=1/2(x-3), f(g(x) = 2(g(x)) + 3 f(g(x) = 2(1/2(x-3)) +3
g(f(x)) = 1/2(f(x)-3)
lol, amistre you fail
:) how so?
i just confuse, i need steps
you just write something them leave.
is there a time limt to wait around for a response? or am i allowed to come back after a response has been given? ;)
i figure with 352 medals, i might be doing something right lol
should we set one?
WB, which steps do you get? That'd be a good start
ok, so plz do step this time.
the beginning,
those are the steps; plug the one into the other; thats all there is to it.
what you plug?
f(x) = 2x+3 means that 'whatever' x equals, plug it in. f(g(x)) simply means that x = g(x)
f(x)=2x+3 and g(x)=1/2(x-3), f(g(x) = 2(g(x)) + 3 f(g(x) = 2(1/2(x-3)) +3 g(f(x)) = 1/2(f(x)-3) g(f(x)) = 1/2(2x+3)-3) then simplify by working out how to remove the parentheses
f(g(x)) = 2(g(x)) +3
ah, got it. thx tonks
all set, then I'm going to go now...jk ;)
f(w) = 2(x) + 3 f(4) = 2(4) + 3 f(applesause) = 2(applesauce) + 3 f(g(x)) = 2(g(x)) + 3 lol
...typed that lol
wait, i have a similar problem, bvut much harder.
the was just the start. and i got he answer, my prof did it on the board.
Tonks has it ;)
thx amistre
WB, post it as a new question, it is easier to find that way
f(x)=-7/2x -3 g(x)=-2x+6/7
this one is much harder.
WB, there's a new thread with this posted, check it out...
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