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Guy how do you integrate (3x^2 + 6) ^ 3 Is it.... {(3x^2 + 6)^4} / 4 ??
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try expanding out the original and then integrating.
Isnt there an eqn in integration stating (ax + b) ^ n is to be integrated normally like the others?
nope, if you took the derivative of what you have above you do not get back the function being integrated.
so the answer that i wrote is wrong?
yep
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(3x^2 + 6)(3x^2 + 6)(3x^2 + 6) = 27x^6+162x^4+324x^2+216 and integrate
What if the whole thing is to the power of half?
what does the problem look like, you may be able to use u-sub?
ill show you....... (3x^2) / squareroot ( x^2 +4)
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That last one you gave looks like a candidate for trig sub.
especially after you factor the 3 out
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