Question

-6x^2 + 48 = 0

Answer 1

subtract 48 from both sides:
-6x^2=-48
divide both sides by (-6):
x^2=8
take square root both sides:
x=sq.rt(2*4)=2sq.rt(2)

Answer 2

add 6x^2 to both sides, divide by 6, that the square root. don't forget the plus or minus

Answer 3

inik i dont think your answer is in a format my teacher is looking for. Right now im doing test corrections and my teacher marked me down for putting the answer as "
+- 8"

Answer 4

\[-6x^2=-48\]
\[6x^2=48\]
\[x^2=\frac{48}{6}=8\]
\[x=\sqrt{8}\] or \[x=-\sqrt{8}\]
and since \[\sqrt{8}=\sqrt{4\times 2}=\sqrt{4}\times \sqrt{2}= 2\sqrt{2}\]
your teacher might prefer the answer written in 'simplest radical form'