Question

I would greatly appreciate any help! Thanks so much
(2x(1/3))/1-(1/3)^2

Answer 1

confused a bit. looks like
\[\frac{2x \times \frac{1}{3}}{1-(\frac{1}{3})^2}\]
but that doesn't really make sense.

Answer 2

perhaps the 'x' is a times sign?

Answer 3

lol oh yes, I'm sorry. The x was a multiplication sign.

Answer 4

ah so it is
\[\frac{2\times \frac{1}{3}}{1-(\frac{1}{3})^2}\]

Answer 5

we get

\[\frac {\frac{2}{3}}{1-\frac{1}{9}}\]

Answer 6

Yes, exactly! And I'm stuck. I got my answer as (18/27)/9 which I highly doubt is correct.

Answer 7

\[=\frac{\frac{2}{3}}{\frac{8}{9}}\]
\[=\frac{2}{3}\times \frac{9}{8}\]
\[=\frac{3}{4}\] if my arithmetic is correct.

Answer 8

How may I ask did you get 8/9?

Answer 9

\[1-\frac{1}{9}=\frac{9}{9}-\frac{1}{9}=\frac{8}{9}\]

Answer 10

lol aye yi yi, thank you so much. I really appreciate it.

Answer 11

welcome!