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please help if an equation of a slope field is y'= (sinx)(siny) . what is the equation of the solution that passes through (0,npi), where n is any integer?
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dy/dx= (sinx)(sin y) dy/(siny)= dx/(sinx) now integrate . -log(cosecy +coty)=-log (cosec x +cot x) -log c* ( put C=logc for easy calculation) cosec y +cot y =c cosec x +c cot x now plug the values cosec x , cot x not defined at 0. and cosec y and cot y not defined at npi. so there is not any real curve whose dy/dx=(sinx)(siny) and passes through (0 npi)
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