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yes, this is easy. what is the area of the sector of a circle with radius r and angle pi/6?
no no, i've got that bit - the area is \[\Pi r ^{2}/12\] for the sector area when the area is halved i need to know the length of 'a'
okay, so half that area is pi r^2 /24 now, he cuts out a triangle half the slice. the triangle is isoceles. its area is 1/2 base times height. the base and height can be got from using the angle(pi/12) and hypotenuse (a)
equate the triangle's area to half the sector's area and get a in terms of r
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NOM NOM cake <3
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