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Mathematics 13 Online
OpenStudy (anonymous):

x^2 <= 3 -2x I factored and got: (x-1)(x+3)<=0 now what?

OpenStudy (anonymous):

now draw a line of numbers, mark -3 and 1 on it. If you are at -infinity till -3 then both factors are negative. Between -3 and 1 x-1 is negative x+3 is positive. After 1 both are positive. Now when will you get something lower than 0? When you multiply -*+ (-*-=+, +*+=+) So the answer is x is greater/equal than -3 and lower/equal than 1.

OpenStudy (anonymous):

I wrote so much just to illustrate my method, but you can do it differently too.

OpenStudy (amistre64):

[-3,1] right?

OpenStudy (anonymous):

sure :)

OpenStudy (amistre64):

i was gonna write a sequal to your novel, but..... ;)

OpenStudy (anonymous):

This was how my favourite teacher taught me! :-)

OpenStudy (anonymous):

is this all for my question?

OpenStudy (amistre64):

i learned it that way as well...

OpenStudy (amistre64):

alot easier than trying to keep track of it in your head :)

OpenStudy (anonymous):

it is always worth making some kind of drawing, helps a lot

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