Question

i need to find the tan(a-b) knowing tan a=5/12, sin $= -4/5 and sec B= 25/24 the restriction is (pi/2)<$ 15 years ago

Answer 1

$ is theta by the way.... ._.

Answer 2

\[tan^{-1}(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}\]
so you need to find \[tan(a)\] and
\[tan(b)\]
you already have \[tan(a)=\frac{5}{12}\]

\[sin(b)=-\frac{4}{5}\]
\[cos(b)=\frac{24}{25}\] because secant is the reciprocal of cosine, so
\[tan(b)=-\frac{5}{6}\] because it is sine over cosine. plug these numbers into the formula and you win.

Answer 3

NO YOU WIN! XD