graph the line that goes through point (3,8) and is parallel to the line whose equation is 6y-10x=30.
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OpenStudy (anonymous):
can some graph this to the question please.
OpenStudy (anonymous):
y=5+5/3x so the line that is parallel to this has to have the same slope (5/3)
You can graph it easily. just go to the point 3,8 and draw a line with 5/3 slope
OpenStudy (anonymous):
this right?
OpenStudy (anonymous):
I cannot see the line.
OpenStudy (anonymous):
watcha mean
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OpenStudy (anonymous):
i graphed it wrong?
OpenStudy (anonymous):
I really cannot see any graph there is just a vertical and horizontal line added
OpenStudy (anonymous):
what did you use to make it?
OpenStudy (anonymous):
o ok paint i copied graph off internet
OpenStudy (anonymous):
hehe :)
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OpenStudy (anonymous):
i did it wrong i made it perpendicullar instead of parallel
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
that makes a bit of difference. just go to the point (3,8) and draw a line with slope 5/3 that means that if you go 1 step right the line will go 5/3 up
OpenStudy (anonymous):
so its just one line right
OpenStudy (anonymous):
lol
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