Question

tan^4 h -1 I need to express this in terms of sin h

Answer 1

\[\tan ^{4}(h-1)=\sin ^{4}(h-1)\div \cos ^{4}(h-1)=\sin ^{4}(h-1)\div (1-\sin ^{2}(h-1))^{2}\]
is it sufficient or you need to simplify more...?

Answer 2

or is it \[tan^4(h)-1\]?

Answer 3

I don't know if I need to simplify more. Can you? and its (h-1)