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4b(a-b)/a
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whats the question
4ab - 4b^2 / a = 4b - 4b^2/a =4b(1-b/a)
multiplying this wouldn't give us 4ab^2/a and then =4b^2?
no because of distributive property 4b*(a-b) = 4ab - 4b^2
ohhhh yes!
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so simplifying this= 4ab-4b^2/a
=4b-4b^2
yes but the 4b^2 term still has a in denominator
Oh, I thought that disappeared with a going into the first problem. So my answer is still 4b-4b^2/a??
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