Question

How do you factor 3x^2+2x-8

Answer 1

You can always solve these kind of problems by solving the above equation =0
You can do that by this formula: \[(-b \pm \sqrt{b ^{2}-4ac})/2\]
where ax^2+bx+c=0
So here: a=3 b=2 c=-8

Answer 2

/2a

Answer 3

so it is -2+-sqrt100/6
that is -2 and 4/3
So the factor is 3(x+2)(x-4/3)

Answer 4

Thank you

Answer 5

No problem

Answer 6

The answer is: (3x-4)(x+2)