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OpenStudy (anonymous):
If a pro basketball player has a vertical leap of about 35 inches, what is his hang time? Use the hang-time function V=48T^2
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OpenStudy (anonymous):
what does V stand for in the formula?
OpenStudy (anonymous):
I think vertical? Not sure..this week in class I have been very confused....
OpenStudy (anonymous):
if it's the vertical distance, then substitute it , 35=48T^2.
OpenStudy (anonymous):
\[35=48T^2\]\[T=\sqrt{35/48}\]
T=.8539 seconds
OpenStudy (anonymous):
yep, that may be right. but what if V turns out to be VELOCITY, though not so likely?
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OpenStudy (anonymous):
It is for vertical leaps
OpenStudy (anonymous):
then .8539 is the answer
OpenStudy (anonymous):
then .8539 is the answer
OpenStudy (anonymous):
I just tried it and it kicked back saying it was wrong as well...cause my answer was close to that as well
OpenStudy (anonymous):
the V means vertical leaps in minutes
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OpenStudy (anonymous):
I mean inches
OpenStudy (anonymous):
Please help me...
OpenStudy (anonymous):
\[\sqrt{9x+67}=x+5\]
OpenStudy (anonymous):
I need this solved...I really am just checking the answers I got wrong to see where I went wrong
OpenStudy (anonymous):
x = 6
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