Mathematics
14 Online
OpenStudy (anonymous):
√3x+6 (+6 is in radical)= x-4
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OpenStudy (anonymous):
square both sides to get rid of square root
OpenStudy (anonymous):
square (x-4)---FOIL
OpenStudy (anonymous):
\[3x + 6 = x^{2} -8x + 16\]
OpenStudy (anonymous):
subtract 3x and 6 to move to right side leaving 0 on the left
OpenStudy (anonymous):
\[x^{2} -11x - 10 =0\]
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OpenStudy (anonymous):
you can factor using chart or my grouping
OpenStudy (anonymous):
sorry that should be +10
OpenStudy (anonymous):
\[x^{2} - 11x + 10 =0\]
OpenStudy (anonymous):
what factors of 10 as a product gives you -11 as a sum?
-1 * -10=10 and -1 + (-10)=-11
OpenStudy (anonymous):
so the factors are -1 and -10
(x-1)(x-10)=0
x-1 = 0 and x-10=0
x=1 x=10
{1, 10}
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OpenStudy (anonymous):
or factoring by grouping-break down middle term using know factors of -1 and-10
OpenStudy (anonymous):
\[x^{2}-x-10x+10\]
OpenStudy (anonymous):
factor out GCF
x(x-1)-10(x-1)=0
(x-10)(x-1)=0
x=10 and x=1
OpenStudy (anonymous):
thx
OpenStudy (anonymous):
welcome...do you understand? what grade are you in...medal please ; )
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OpenStudy (anonymous):
im in 8th doing algebra, so what ur final answer?
OpenStudy (anonymous):
and what are you talking about with a medal?
OpenStudy (anonymous):
love 8th grade Algebra! Solutions are 10 and 1
{1, 10}
OpenStudy (anonymous):
click on good answer by my name on the right
OpenStudy (anonymous):
yeah i got that, but when you plug it back in, it doesnt work. does it have to work?
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OpenStudy (anonymous):
what answer do i click on for good answer?
OpenStudy (anonymous):
it does work
OpenStudy (anonymous):
\[x=1 \sqrt{9}=1-4\]
OpenStudy (anonymous):
okay good, thanks for your help
OpenStudy (anonymous):
square root of 9 is 3 or -3
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OpenStudy (anonymous):
wait could u also help me with another question instead of me reposting one??
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
x=10 so square root of 36 equals -6 or 6
OpenStudy (anonymous):
a right triangle has one leg that is 4 inches shorter than the other leg. the hypotenuse is √106 inches. find the lengths of the legs.
OpenStudy (anonymous):
ok i'm writing it out to solve...hold on
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OpenStudy (anonymous):
k
OpenStudy (anonymous):
ill be right back
OpenStudy (anonymous):
do you want to factor my grouping
OpenStudy (anonymous):
\[2x^{2}-8x-90=0\]
OpenStudy (anonymous):
let a = x, b=(x-4) and c=square root of 106(hypotenuse)
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OpenStudy (anonymous):
\[x^{2} + x^{2} -8x +16 = 106\]
OpenStudy (anonymous):
after plugging into Pythagorean Theorem (right triangle)
OpenStudy (anonymous):
subtract 106 from both sides to get the first equation I posted above
OpenStudy (anonymous):
back
OpenStudy (anonymous):
working backwards so hope you can follow
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OpenStudy (anonymous):
kind of
OpenStudy (anonymous):
where did you get lost?
OpenStudy (anonymous):
thx