Compute the distance Mark will run if he continues using the formula, y = 10(1.1)x, for 52 weeks (one year). Does this distance seem reasonable?
A. yes
B. no
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OpenStudy (anonymous):
x exponent
OpenStudy (anonymous):
does it represent weeks or years
OpenStudy (anonymous):
the x exponent represents both i think bc 52 weeks is one year isnt it?
OpenStudy (anonymous):
yes but if you use years then you would use 1 versus 52(weeks)
OpenStudy (anonymous):
usually years unless otherwise stated in problem
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OpenStudy (anonymous):
So then lets use 52 weeks (: for the answer i got 1291.3miles in 52 weeks
OpenStudy (anonymous):
if you use 52 then you should get 1420.42932
OpenStudy (anonymous):
Hmmmm so what do you think the answer would be? (:
OpenStudy (anonymous):
what are the units
OpenStudy (anonymous):
seems reasonable from what info you gave and if we use 52
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OpenStudy (anonymous):
alright so the answer would be true? >.< kinda confused lol
OpenStudy (anonymous):
If y is the distance traveled in x weeks, then, as btm said, the distance traveled is:
\[y=10(1.1)^{52}\approx1,420\]
So, Mark would run 1420 length unit in 52 weeks.