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OpenStudy (anonymous):
2x-3 divided by 4x^4 - 8x^3 + 6x^2 - 3x + 2
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OpenStudy (anonymous):
can you factor out the second part where you have something like 2x-3( w/e) so you can have \[\frac{2x-3}{2x-3(w/e)}= \frac{1}{(w/e)}\]
OpenStudy (anonymous):
is this possible?
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