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Put the equation in the form ax^2+bx+c=0 7-3x^2=(x+2)^2-6
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expand and combine
(x+2)^2 expands into what?
x^2+4
very close; good effort; but lets do this the long way to see what we get... (x+2) (x+2) ; distribute it out once like this: (x+2)(x) + (x+2)(2) ; now distribute it thru again like this: xx + 2x + 2x + 4 ; now combine the terms that look the same x^2 +4x +4
now lets put this exapnded form to good use: 7 -3x^2 = (x^2 +4x +4) -6 7 -3x^2 = x^2 +4x +4 -6 put it all to one side; i choose right. 0 = -7 +3x^2 +x^2 +4x +4 -6 ; add everything that looks the same 0 = 4x^2 + 4x -9 right?
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yep thats right
yay!! ... i do mess up alot and its nice to have confirmation :)
no problem
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