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OpenStudy (amistre64):
y=-(5/2)^2+5(5/2)+6
y = -25/4 + 25/2 +6......... yup
OpenStudy (anonymous):
See: do you know differentiation?
OpenStudy (anonymous):
ya very well.
OpenStudy (anonymous):
Ok. so when you differentiate ax^2+bx+c
and equate it to 0, you get -b/2a
Putting this in fn: you get -D/4a
OpenStudy (anonymous):
-D/4a?how?
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OpenStudy (anonymous):
See: did u get y i differentiated?
OpenStudy (anonymous):
plz tell me the reasion?
OpenStudy (anonymous):
ok when we differentiate, we get the eqn of the slopes of that eqn on respective pts
OpenStudy (anonymous):
why we want to know slope?
OpenStudy (anonymous):
tell me what you know about derivative at a pt?
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OpenStudy (anonymous):
i have done intermediate level
OpenStudy (anonymous):
ok. its the limiting secant to the graph, the tangent!
OpenStudy (anonymous):
bec of tangent we differentiate ya?
OpenStudy (anonymous):
not actually, derivative is also the rate, you can say,
See the more slope a pt has, wouldn't it turn more? What I mean is if it has more slope it will increase faster!
OpenStudy (anonymous):
ok thanks amogh
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OpenStudy (anonymous):
So you understand why we equate the slope to 0?
OpenStudy (anonymous):
actually iam not intouch.
OpenStudy (anonymous):
hmm...np was i clear enough?
OpenStudy (anonymous):
thanks alot amogh
OpenStudy (anonymous):
LOL, I'm askin you did u understood wat i said now?
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OpenStudy (anonymous):
or i was too fast or slow?
OpenStudy (anonymous):
u was splended amogh
OpenStudy (anonymous):
Determine the vertex of the given equation.
y = x2 + 9? im Haveing trouble.