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Mathematics 22 Online
OpenStudy (anonymous):

1/3logx + 4log(x+5) Please show work!

OpenStudy (anonymous):

what are you supposed to do?

OpenStudy (anonymous):

Write each as a single logarithm, sorry.

OpenStudy (anonymous):

oh that is easy, just remember the basic logarithm rules

OpenStudy (anonymous):

http://www.purplemath.com/modules/logrules.htm

OpenStudy (anonymous):

first change 1/3logx into log ((x^1/3)) and 4log (x+5) into log (x+5)^4 and not log a + logb= log ab So log(x+5)^4)*x^1/3) is the result

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