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1/3logx + 4log(x+5) Please show work!
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what are you supposed to do?
Write each as a single logarithm, sorry.
oh that is easy, just remember the basic logarithm rules
first change 1/3logx into log ((x^1/3)) and 4log (x+5) into log (x+5)^4 and not log a + logb= log ab So log(x+5)^4)*x^1/3) is the result
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