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OpenStudy (anonymous):
I need to find the slope and y-intercept of
x+5y=10
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OpenStudy (anonymous):
do you know the slope intercept form of a line?
OpenStudy (anonymous):
this math confuses me, I know y=mx+b, but I am not sure how to get there from the way that the problem is stated
OpenStudy (anonymous):
okay. y = mx +b where m is the slope and b is the y intercept.
now, x+5y = 10
subtract x from both sides and then divide by 5.
OpenStudy (anonymous):
x=-2
OpenStudy (anonymous):
x+5y = 10
5y = -x+10
y = -x/5 + 2
slope is -1/5, y-intercept is 2
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OpenStudy (anonymous):
x+ 5y - x = 10-x subtract x from both sides
5y = -x+10
y = (-x/5) + 2 divide both sides by 5
y = (-1/5)x+2
OpenStudy (anonymous):
x+5y=10
5y= -x+10
y=-x+2
m= -1
b=2
OpenStudy (anonymous):
AntsOfDglgmut.. what would my graphing points be..
OpenStudy (anonymous):
slope is -1 and y int is 2
OpenStudy (anonymous):
well your y-intercept is just the point (0,2) you can plug in points to your original equation to find other points.
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OpenStudy (anonymous):
and don't listen to kenya.
OpenStudy (anonymous):
y i did it rite
OpenStudy (anonymous):
no you didn't. you didn't divide -x by 5.
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