Question

someone wanna help me?
x squared = 12 ...solve using square root property?

Answer 1

Take square root of both sides.

Answer 2

so its x=3 rad 2?

Answer 3

What is the square root over the two or the three?

Answer 4

idk?

Answer 5

That's not a good answer.

Answer 6

idk how to solve this problem? i dont know what the sqauare root of 12 is. all i no is that it is 3 rad 2......what else do i need to do?

Answer 7

You keep the 12 under the radical and break it down: 2.2.3 all under the square root sign.

Answer 8

well...so its not 3 square root of 2?

Answer 9

Right. Actually it is sq rt 4=2

Answer 10

how is it the square root of 4?

Answer 11

sq rt of 12 is equal to sq rt of (4.3)

Answer 12

Not to confuse you, I was just correcting your statement\[2\sqrt{3}\]

Answer 13

so is square root of (x-5) ^ 2 = sqaure root of 2 does x =6?

Answer 14

What?! You lost me.

Answer 15

ok i feel dumb. ok solve this using the square root property x-5 ^ 2 =2

Answer 16

i got 6

Answer 17

Same process: sq rt of both sides.

Answer 18

ok i did and got x-5 = 1

Answer 19

sq rt of 2 is not 1

Answer 20

o...well 2/2 = 1

Answer 21

That is correct, but not part of this problem.

Answer 22

ugh ok so what is the square root of 2?

Answer 23

Sq rt of 2 is sq rt of 2.

Answer 24

but i have to simplyfy ? whats the answer of the equartion then? just x-5 = sqr 2?

Answer 25

You can get a number by using calculator, but since you are studying sq rt you can leave it in that form, same way you left sq rt of 3 in previous problem

Answer 26

do you no how to compelte the square?

Answer 27

Yes, it's that thingy where you divide by 2, then square it

Answer 28

ok x ^ 2 - 8x = 3

Answer 29

slve by completing the squarue

Answer 30

You take that thing in front of x, divide it by 2, square it, add it to each side.

Answer 31

???
can u write it out?

Answer 32

theres nothing infront of x

Answer 33

Looks like -8 to me.

Answer 34

oo yeah i got u

Answer 35

so it would be 16x ^ 2 - 4x = 19?

Answer 36

You did more than my instructions said, the x^2 -8x remains part of the equation, the thing you calculated is added but they are apples and oranges you just write it in.

Answer 37

so how would you write it?

Answer 38

\[x ^{2}-8x+16=3+16\]

Answer 39

ok a couple more.... how would you do 1+5i/3-2i

Answer 40

Have to look up my old notes, been a while.

Answer 41

ok

Answer 42

You have to do conjugation: multiply by (3+2i)/(3+2i)

Answer 43

wait how can u multiply and divide at the same time??

Answer 44

its 2AM...im sorry im sooo tired but this is due at 8AM

Answer 45

You have to manipulate your original problem in order to have something to work with. The choice of conjugation is an off-shoot of the bottom term of your problem. In math you can't change things but you can do tricks, for example if you multiply by 1, you have not changed anything. The thing I told you to multiply is equal to 1.

Answer 46

ok so how do u solve the problem?

Answer 47

You use the FOIL method multiply top
The top looks like this (1+5i)(3+2i)
The bottom is (3-2i)(3+2i)

Answer 48

i got 13 + 17i

Answer 49

I assume you are working on the top only, recall FOIL method: First, Outside, Inside, Lasts. Be careful to add only like terms, add apples to apples and oranges to oranges.

Answer 50

that what i did
cuz u said the bottom = 1

Answer 51

Well, the bottom is not equal to 1, the whole term I introduced is equal to 1. You skip to many steps. Take baby steps, produce the terms of FOIL, eg First is1x3=3

Answer 52

ok .... this is the answer i got..of its wrong just tell me the answer....... 13+17i / 13-12i

Answer 53

You can't get that, my first term is 3

Answer 54

3+ 2i +15i +10i^2 which i^2 = -1
over 9-6i -6 - 4i^2

Answer 55

?

Answer 56

That's it you got rid of some of the i's but there is still one left in top, must check notes again.

Answer 57

ok how do you do 6/cube root of 29?

Answer 58

Not much you can do with that, if you are work with cube roots like you were with square roots.

Answer 59

o snap
i wrote that wrong... i meant 6/cube root of 2a ^ 2 sorry!

Answer 60

I am looking over my notes for complex numbers, you are doing everything right; seems the point is to at least get it out of the bottom. Break it down as much you can, final answer would have i in it.

Answer 61

i need that rationalized

Answer 62

For these, they just want you to move square root out of the the bottom. So the same process as complex number, you multiply by\[\sqrt[3]{2a ^{2}}/\sqrt[3]{2a ^{2}}\]

Answer 63

so it would be 6 cube root 2a ^2
over ????

Answer 64

If you multiply cube root of something by cube root of something you would get something. So the answer is whatever is under radical.

Answer 65

2a?
is the top right?

Answer 66

2a^2, yes top is right.

Answer 67

ok last problem!! square root of 2x+11 =5

Answer 68

You do the opposite of earlier problems: square both sides.

Answer 69

7?

Answer 70

You skipped to many steps. Jumping in shower.

Answer 71

im going to bed night