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Help please... I'm terrible at math can someone tell me the value of X and how to find it? This is the problem 5^(x-1)=2^x
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\[5^{x-1}=2^x\] take log of both side \[\log 5^{x-1}=\log 2^x\] pull out the exponent \[{x-1}\log 5=xlog 2\]
xlog 5 -log5=xlog2 xlog 5-xlog2=log5
x(log 5 - log 2)=log 5
Thank you so much... but... what is X?
divide both side by (log 5- log 2) then you would have x by itself
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