i have just a couple more questions as I am trying to teach myself the steps to figure these , i want to write an equation of a line that passes through point(2,5) and has a slope of 3.

Question

anonymous · Answer

okay, there are two nice equations to know for solving an equation of a line
Point slope:
y-b = m (x-a)  
Slope-intercept Form:
y=mx +b  
For both you need the slope and a point the equation needs to pass through.
For point slope, if you have slope 3 and Point A = (a,b) (or in your case (2,5))
y-5 = 3(x-2)

In slope-intercept form, you plug in values of y & x to get b
y=3x +b
5 = 6 +b
b=-1
y= 3x -1

anonymous · Answer

So Y=Mx+b is the normal equation of a line... so then just add 3 over 1 so it would be y=3over1x

anonymous · Answer

don't i have to go any further once i came to  y=3x-1?