Question

How do I solve dy/dx = (y-1)^2? y(0)=1

Answer 1

dy/(y-1)^2 = dx
-1/(y-1) = x+c

Answer 2

yd/dx (y-1 ^ 2 ) = (y-1)^(2-1)
y(0) = 0-1 = -1 !

Answer 3

this must be wrong///

Answer 4

it must be dx/dy instead of dy/dx

Answer 5

my teacher mentioned this type of problem

Answer 6

-1/(x+c) = y-1
y=(x+c-1)/(x+c)
now
put the values 0,1
c-1/c = 0
c=1

Answer 7

there you go

Answer 8

thank you

Answer 9

click on good answer to complete my century plz ;)

Answer 10

thnx