Somebody please help me with a:
False point method for solution of equations
Question (A-level U.K. maths)

Question

anonymous · Answer

attachment

anonymous · Answer

The second half of the question..

anonymous · Answer

x = (0f(1) - 1f(0))/(f(0)-f(1))

amistre64 · Answer

false point method?  dont they call that Newtons approximation?

anonymous · Answer

all i could get

amistre64 · Answer

x^5 -5x +1; if we pick x=2 perhaps; then we want the equation of the tangelnt line at x=2 (2,23)

5(2)^4 -5 = 75

23 - 7(2) = b

y = 75x + 9 = 0 when x = -75/9  = -8' 1/3

did I do it right?

anonymous · Answer

you have to use the function of 1 and 0 because they have opposite signs and therefore straddle the root, a line is constructed inbetweeen them to get a new approximation of x, but what you did for newton raphsons method is right! :)
im not sure if my workings are correct...