So i'm trying to study for a final exam. I found this practice problem online that said: What is the slope of a line parallel to the graph of 3x-5y=18. Am i suppose to use a slope intercept formula or something?
frist write sope intercept from, u know how to writer it?
so you do use it? or are there any other formulas that are also acceptable
what formulas? I don't get the question u ask
well, i have no idea how to do the problem. thats all, so i'm just guessing
find slope or write slope intercept from pass 2 point or paralell form this equation 3x-5y=18.
y=mx+b? y=3x+18? is that it
y=mx+b? y=3x+18 is call slope intercept
yeah okay. just asking if i plugged it in right.
yes you r
slpoe =3x if another line the same 3x than they are paralell
yes you r soppese to
\[\sqrt{?}\]vvvvvv
okay so next step.is must be 3 over something.....
3x-5y=18 y= (-3x+18)/-5 y = (3/5x)-(18/5)
\[y=\frac{3x}{5}-\frac{18}{5}\]
ok thanks! i see now
u r welcom If I deserve medal then give me one.
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