A footbridge is in the shape of an arc of a circle. The bridge is 6 ft tall and 25 ft wide. What is the radius of the circle that contains the bridge?

Question

anonymous · Answer

wouldnt it be half of 25?

anonymous · Answer

maybe, but then whats the 6 for?

anonymous · Answer

thats what i couldnt figure out

anonymous · Answer

haha it's confusing.

anonymous · Answer

i'll keep trying ha

anonymous · Answer

i really dont know though sorry!

amistre64 · Answer

i do :)

anonymous · Answer

it okaye michelle(: haha 
and can you help then.? :P

amistre64 · Answer

w^2
----- + rise/2  its how i made a thousand arches
rise/8

amistre64 · Answer

25^2/6 = n

n/8 = m

m+ 6/2 = radius

amistre64 · Answer

abt 16.02

amistre64 · Answer

we would have walkthrus that the prints needed arches so high by so wide; i figured id find a formula for determing how far to put my pivot point to attc my chalkline or tape to so I could make the required arch

amistre64 · Answer

width^2
------ + rise/2 = radius of circle
 rise/8