Question

Algebraically determine the x-intercept and y-intercept. x/5+y/2=1

Answer 1

Set \(x=0\) we have \(y/2=1\). So \(y=2\). Hence (0,2) is the y-intercept.
Set \(y=0\) we have \(x/5=1\). SO \(x=5\). Hence (5,0) is the x-intercept.

Answer 2

How would I write out that equation in slope-intercept form?

Answer 3

You just need to isolate the \(y\). First move the \(x/5\)
\(y/2=-x/5+1\)
Then multiply by 2
\(y=-\frac{2}{5}x+2\)