Mathematics
21 Online
OpenStudy (anonymous):
Find the area of a regular hexagon with sides 12 ft
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
A = 1/2 ap
OpenStudy (anonymous):
Any takers!
OpenStudy (anonymous):
Help me....
OpenStudy (radar):
I'm thinking lol
OpenStudy (radar):
We need to calculate height: The height is \[\sqrt{12^{2}-6^{2}}=\sqrt{144-36}=\sqrt{108}\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
oh thank you radar.... I think this is the last one! Cause I quit! LOL
OpenStudy (radar):
Area for a regular hexagon is: A= 1/2 (6sh)
A=.5 x6 x 12 x sqrt 108=374.123 sq ft
OpenStudy (radar):
s is side length, h is height A is area.
OpenStudy (anonymous):
ok
OpenStudy (amistre64):
you gots it?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
shhhh... no lol
OpenStudy (amistre64):
hex=6 sides right?
OpenStudy (anonymous):
yeppers
OpenStudy (amistre64):
360/6 = 60 degrees for central angles then and an outer side at 12; law of cosines modified will give us lengths of sides
OpenStudy (amistre64):
12^2 = 2s^2 - 2(s)(s)(cos(60))
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
144 = 2s^2 (1 - cos(60))
144/ (1 - cos(60)) = 2s^2
144/ (1 - cos(60))
---------------- = s^2
2
s = sqrt(all that) lol
OpenStudy (anonymous):
yikes not diggin the cos stuff....
OpenStudy (amistre64):
6.0726801....
OpenStudy (amistre64):
all that does is give me a side to go off of to caluclate the area of one tri and then gonna multiply by 6 for the whole thing
OpenStudy (anonymous):
oh danger... I think the answer is going to be ?\[\sqrt{?}\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
lol
OpenStudy (amistre64):
it might be :)
OpenStudy (anonymous):
is that 6.0726801 the area?
OpenStudy (amistre64):
thats the length of a side
OpenStudy (anonymous):
ewe
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
we got an isoceles trianlgle with a base of 12 and a top angle of 60
OpenStudy (amistre64):
if I know the length of the sides I can caluclate the area for on tri pieces of the hex
OpenStudy (anonymous):
216 square root 3
OpenStudy (amistre64):
12^2 = s^2 + s^2 - 2ss cos(60)
144 = 2s^2 - 2s^2 cos(60)
144 = 2s^2(1 - cos(60))
144
---------- = 2s^2
(1-2cos(60))
72
---------- = s^2
(1-2cos(60))
72
sqrt[ ----------- ] = s
(1-2cos(60))
OpenStudy (amistre64):
s*s*sin(60)
---------- = area of tri piece; 6 of those is the whole thing right?
2
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
right cause its a 6 sided polygon?!
OpenStudy (amistre64):
sqrt*sqrt = innards
OpenStudy (amistre64):
yes
OpenStudy (amistre64):
that 2cos is a typo.... that denom is sposed to be 1-cos(60)
OpenStudy (amistre64):
72 sin(60)
------------ = area of tri
2 (1-cos(60))
36 sin(60)
-----------
(1-cos(60))
36 (sqrt(3)/2)
-------------
(1-(1/2))
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
18 sqrt(3)
--------- = 36sqrt(3) right?
1/2
OpenStudy (amistre64):
times 6 = 216 sqrt(3)
OpenStudy (anonymous):
lol here...
A = 1/2 ap
A= 1/2 (6sqrt3)(72)
216sqrt3 = 374.1cm sq
OpenStudy (anonymous):
YOU GOT IT!!!!!!!!!!!!!
OpenStudy (amistre64):
I did lol
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
and it matches mine :) Good Business! You soooo hired!! LOL
OpenStudy (anonymous):
are
OpenStudy (amistre64):
yay!!.... and i did it all with one brain cell tied behind my cerebellum ;)
OpenStudy (anonymous):
Hilarious!! You rock!
OpenStudy (amistre64):
gotta go write some homework.... have fun ;)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
thank you!
OpenStudy (radar):
I was right, he got the same answer lol
OpenStudy (radar):
How did it become centimeters, I thought it was 12 ft
OpenStudy (anonymous):
ft squared lol
OpenStudy (radar):
Great, good luck with your studies.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ha thanks