Question

any help on #3?? attachment?

Answer 1

Attachment?

Answer 2

?

Answer 3

Ohhh haha it wasnt showing on my screen sorry

Answer 4

its hard as heak?

Answer 5

\[-1000 +\frac{1500x}{\sqrt{400+x^2}}=0\]

Answer 6

no #3

Answer 7

whicih #3 then lol

Answer 8

the long paragraph

Answer 9

ooooo.... this one again

Answer 10

ideally when the beach pipe cost equals the sea pipe cost you reach a balance point

Answer 11

b(1000) + s(1500) = Equilibrium

we just have to get a formula to equate b and to plug in

Answer 12

s = sqrt(20^2 + (b-x)^2) where b-x is the distance between the rig and the shore pipe

Answer 13

thats about the best i can do for equating the s and b

Answer 14

b(1000) + sqrt(20^2 + (b-x)^2)(1500) = E

solve for b right?

Answer 15

yes x is the distance from the oil rigs vertical line to the shoreline..

Answer 16

well it says my answer will be in terms of x?...

Answer 17

maybe better like this tho:

when b(1000) = s(1500)

b(1000) = sqrt(20^2 + (b-x)^2)(1500)

b(1000)/1500 = sqrt(20^2 + (b-x)^2)

2b/3 = sqrt(20^2 + (b-x)^2) ; ^2 both sides

Answer 18

4b^2
---- = 400 + (b-x)^2
9


4b^2
----- = 400 + b^2 -2bx +x^2
9


4b^2 = 9(400 + b^2 -2bx +x^2)

4b^2 = 3600 + 9b^2 -18bx +9x^2

Answer 19

4b^2 = 3600 + 9b^2 -18bx +9x^2

0 = (5)b^2 -(18x)b + (9x^2 + 3600) perhaps?

Answer 20

to solve for b we can use the quadratic formula and insert all this other stuff as parameters

Answer 21

18x sqrt(324x^2 - 4(5)(9x^2 + 3600))
--- + ----------------------------- and simplify lol
10 10

Answer 22

sqrt(144x^2 - 72000) looks possible :)

Answer 23

holy bageezus ... i uderstand the transitions and all ..and everything your doing ..but what are parameters?

Answer 24

parameters are just the values we plug into the quadratic formula to make this easier; they relate to the coeffs of the b values

Answer 25

oh okay!.

Answer 26

so we cant reduce the last step by 12 or anything?

Answer 27

sqrt(144x^2 - 72000) the innards here factor to what:

sqrt(144(x^2 - 500))

12 sqrt(x^2 - 500) if i did that part right lol

Answer 28

our options for b are then:

9x 6sqrt(x^2 - 500)
-- +- -------------- right?
5 5

Answer 29

would the 500 then be 100?

Answer 30

the 500 cant reduce the way i have it

Answer 31

\[\frac{9x \pm 6 \sqrt{x^2 - 500}}{5}\]

Answer 32

okay so we just add the numerators over 5!...yay!!

Answer 33

if this is b we should be able to add this to x and get 30 right?

Answer 34

OMGEE YES!!!!!

Answer 35

you are amazing!!!!

Answer 36

are you a professor or something?/

Answer 37

just a something....

Answer 38

haha mysterious i understand you a secret agent for the mathematical race of under delinquents?!?!?

Answer 39

haha jk well thanks for the help!!

Answer 40

:) libraries closing soon, so good luck with the rest; and I hope that helped out :)