how would i find the vert. and horz. asymtope of
y=5 over x?

Question

how would i find the vert. and horz. asymtope of 
y=5 over x?

anonymous · Answer

vertical asymptote is where the equation is undefined.  
$$y=\frac{1}{x}$$ is not defined at 0 because $$\frac{1}{0}$$ is not a number.  
so the vertical asymptote is given by the equation 
$$x=0$$ otherwise known as the y- axis.

the horizontal asymptote is the line the graph approaches as 
$$x->\infty$$
as x gets large 
$$\frac{1}{x}$$ gets close to zero.  think about 
$$\frac{1}{1000000}=.000001$$
likewise $$x->-\infty$$ y also gets very small.  so the horizontal asymptote is the line $$y=0$$

anonymous · Answer

find vertical asymptote: set denominator = 0 and solve.
horizontal asymptote: 
a) if the degree of the denominator is greater than the degree of the numerator it is y - 0
b) if the degree of the numerator is bigger there isn't one.
c) if the degrees are the same it is y = ratio of leading coefficients.