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Mathematics 20 Online
OpenStudy (anonymous):

let f(x)= 2^+x^2, then f(-1)

OpenStudy (anonymous):

can anyone solve this?

OpenStudy (anonymous):

1/2

OpenStudy (anonymous):

no i sorry it

OpenStudy (anonymous):

2

OpenStudy (anonymous):

2^(?)+x^2

OpenStudy (anonymous):

is the information complete?

OpenStudy (anonymous):

just replace the value of x=-1

OpenStudy (anonymous):

oh sorry! 2^x *

OpenStudy (anonymous):

2 is the answer

OpenStudy (anonymous):

now its complete

OpenStudy (anonymous):

hmmm i tried it and nothigng gave me 2

OpenStudy (anonymous):

it's 2 actually

OpenStudy (anonymous):

square of a negative is positive. so, if you square -1, the answer is 1..and 2 raised to 1 is 2

OpenStudy (anonymous):

pat18 the answer no is 1/2 can rectify!!!

OpenStudy (anonymous):

norbeybarajas-the answer is 2.

OpenStudy (anonymous):

the value of x is -1

OpenStudy (anonymous):

its not. because the choices given does not include a 2 :S

OpenStudy (anonymous):

are you sure?

OpenStudy (anonymous):

what are the choices?

OpenStudy (anonymous):

sorry the answer is 2

OpenStudy (anonymous):

see, it is 2.,

OpenStudy (anonymous):

yes you're right

OpenStudy (anonymous):

thanks.:)

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