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An object is placed in 68 F room. write a differentiatal equation for H , the temperature of the object at time t.
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\[dH/dt = -k(H-68)\]
why is it a negative k
Well, the negative indicates that the rate of change is going down: The closer you get to 68 degrees, the more slowly you change temperature. k is just a constant :D
is it safe to say that when we are dealing with temperature it will bee a negative k
No. It HAS TO BE A NEGATIVE K. This is RATE, not the actual temperature.
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okay . so i am trying to the problem but the differential equation has been written like this dH/dt=k(68−H)
do you know why?
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