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How do you solve: square root of (x+6)=x
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x=3 and x=-2
just square both sides, and you will get a quadratic equation, then factor it out.
square root (x+6) = x Square both sides x+6 = x^2 x^2-x-6 = 0 (x-3)(x+2) = 0 x-3 = 0 x = 3 x+2 = 0 x = -2 Even though x=3 and x=-2 the only solution is x=3 because of the following: square root (3+6) = 3 Square root 9 = 3 which is a true statement square root (-2+6) = square root 4 = 2 but the second solution states that x=-2 and therefore the square root 4 does not equal -2
-2 is a extraneous root
it is an extraneous root
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